“Given a dictionary grades = 'Alice': [85,90], 'Bob': [78,82], 'Charlie': [92,88] , print each student’s name and their average grade.”
[1, 4, 9, 16, 25]
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: This problem tests your understanding of if-elif-else chains. The key is to ensure your conditions don't overlap and cover all possibilities.
Extracting specific characters using string[index] (remembering that Python uses 0-based indexing). “Given a dictionary grades = 'Alice': [85,90], 'Bob':
Remember: are a resource, not a shortcut. Use this guide to unblock yourself, but always experiment further. Happy coding!
# Standard setup for Code Avengers dictionary tasks user_profiles = "player1": "score": 2500, "level": 14, "status": "active", "player2": "score": 4100, "level": 22, "status": "idle" # Accessing nested data safely current_player = "player1" player_score = user_profiles[current_player]["score"] print(f"current_player has a score of player_score.") Use code with caution. : This problem tests your understanding of if-elif-else
If your code looks correct but the platform still marks it as incorrect, check for these platform-specific quirks:
grades = 'Alice': [85,90], 'Bob': [78,82], 'Charlie': [92,88] for student, scores in grades.items(): average = sum(scores) / len(scores) print(f"student: average:.1f")